Fortran可以使用隐形DO循環和reshape給一維和多元數組賦初值.
下面以一維數組和二維數組為例,并給出程式結果:
program main
implicit none
integer::i,j
integer::a(3)=(/(3*j,j=1,3,1)/)
integer::b(6)=(/((i,i=1,2),4*j,j=1,2,1)/)
real::c(2,4)=reshape((/1,(i,i=3,8),10/),(/2,4/))
write(*,*) 'a(3):',a
write(*,*) 'b(6):',b
write(*,*) '!---------------------------------------'
write(*,*) 'c(1,:)',c(1,:)
write(*,*) 'c(2,:)',c(2,:)
write(*,*) '!-----------------------------------------'
end program main
輸出結果如下:
![](https://img.laitimes.com/img/9ZDMuAjOiMmIsIjOiQnIsISPrdEZwZ1Rh5WNXp1bwNjW1ZUba9VZwlHdsATOfd3bkFGazxCMx8VesATMfhHLlN3XnxCMwEzX0xiRGZkRGZ0Xy9GbvNGLpZTY1EmMZVDUSFTU4VFRR9Fd4VGdsYTMfVmepNHLrJXYtJXZ0F2dvwVZnFWbp1zczV2YvJHctM3cv1Ce-cmbw5SOiVmZyE2MzIzN4YGNwYGN3IjN2MTM5I2YidzMzMjYw8CX0AzLchDMxIDMy8CXn9Gbi9CXzV2Zh1WavwVbvNmLvR3YxUjL3M3Lc9CX6MHc0RHaiojIsJye.png)
賦初值時可能符号(/,...,/)看着不太舒服,gfortran容許使用'['和']'來代替:
program main
implicit none
integer::i,j
integer::a(3)=[(3*j,j=1,3,1)]
integer::b(6)=[((i,i=1,2),4*j,j=1,2,1)]
real::c(2,4)=reshape([1,(i,i=3,8),10],(/2,4/))
write(*,*) 'a(3):',a
write(*,*) 'b(6):',b
write(*,*) '!---------------------------------------'
write(*,*) 'c(1,:)',c(1,:)
write(*,*) 'c(2,:)',c(2,:)
write(*,*) '!-----------------------------------------'
end program main