建立XML來發送到伺服器。

建立XML來發送到伺服器。

在Unity裡，我沒有找到可以不添加大量排行來做這個的标準函數，是以我建立了下述機制：

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public  string buildXMLRPCRequest(Hashtable FieldArray,string MethodName) { string  ReturnString = "" ; ReturnString    +=         "<?xml version=\"1.0\" encoding=\"iso-8859-1\"?>" + "\n" + "<simpleRPC version=\"0.9\">" + "\n" + "<methodCall>" + "\n" + "<methodName>" + MethodName + "</methodName>" + "\n" + "<vector type=\"struct\">" ; ReturnString    +=  buildNode(FieldArray); ReturnString    +=  "\n</vector>" + "\n</methodCall>" + "\n</simpleRPC>" ; return ReturnString; } public  string buildNode(Hashtable FieldArray) { string  ReturnList = "" ; foreach (DictionaryEntry Item in FieldArray)    { string  TypeName    =   "int" ; string  NodeType    =   "scalar" ; Type myType =   Item.Value.GetType(); string  fieldValue  =   "" ; if (myType == typeof (string) ) { TypeName    =   "string" ; fieldValue  =   Item.Value.ToString(); } if (myType == typeof (Hashtable) ) { fieldValue  =   buildNode(Item.Value as Hashtable); NodeType    =   "vector" ; TypeName    =   "struct" ; } if (myType == typeof (int) ) { fieldValue  =   Item.Value.ToString(); TypeName    = "int" ; } var ThisNode    =   "\n<" + NodeType + " type=\"" + TypeName + "\" id=\"" + Item.Key + "\">" + fieldValue + "</" + NodeType + ">" ; ReturnList +=   ThisNode; } return ReturnList; }

buildXMLRPCRequest 是用來建立 XML的。

你想要編碼的字段HashTable可能包括types: int, string 或者 Hashtable的對象。它将傳回精美格式化的（簡單）XML-RPC字元串，準備發送到伺服器。

發送

把XML發送到伺服器，你需要發出帶有設定為text/xml的mine類型post請求。标準C#函數沒有一個能用于Unity的，但是用這種buildXMLRPCRequest邏輯輸出非常有效，它所做的是：

在Unity發送：

我使用這個代碼：

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private     void UnityPostXML(  int Staging, string WebServer, string MethodName, Hashtable   FieldArray) { string  WebServiceURL   =   "http://LIVESERVER/" ; if (Staging == 1) { WebServiceURL       =   "http://TESTSERVER" ; } // Encode the text to a UTF8 byte arrray string XMLRequest   =   buildXMLRPCRequest(FieldArray,MethodName); System.Text.Encoding enc = System.Text.Encoding.UTF8; byte[] myByteArray = enc.GetBytes(XMLRequest); // Get the Unity WWWForm object (a post version) var form = new WWWForm(); var url = WebServiceURL; //  Add a custom header to the request. //  Change the content type to xml and set the character set var headers = form.headers; headers[ "Content-Type" ]= "text/xml;charset=UTF-8" ; // Post a request to an URL with our rawXMLData and custom headers var www = new WWW(WebServiceURL, myByteArray, headers); //  Start a co-routine which will wait until our servers comes back StartCoroutine(WaitForRequest(www)); } IEnumerator WaitForRequest(WWW www) { yield return www; // check for errors if (www.error == null ) { Debug.Log( "WWW Ok!: " + www.text); } else { Debug.Log( "WWW Error: " + www.error); }    }

• 用UTF8把XML編碼成ByteArray

• 建立一個新的Unity WWWForm

• 建立HashTable, 存儲目前的http标頭，覆寫内容類型為text/xml。

• 發送lot給server

• 建立協程等待答複

不适用Unity發送

我發現使用C#（MonoDevelop)的标準版本）開發library比用Uinty開發一切簡單多了。是以如果想用C#做同樣的邏輯發送，如下：

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private     string NormalXMLCall(int Staging, string WebServer, string MethodName, Hashtable Fields) { //  Figure out who to call string  WebServiceURL   =   "http://LIVSERVER" ; if (Staging == 1) { WebServiceURL       =   "http://TESTSERVER" ; } WebServiceURL           +=  WebServer; //  Build the request XmlRpcParser    parser  =   new XmlRpcParser(); string XMLRequest       = parser.buildXMLRPCRequest(Fields,MethodName); //  Fire it off HttpWebRequest httpRequest =(HttpWebRequest)WebRequest.Create(WebServiceURL); httpRequest.Method = "POST" ; //Defining the type of the posted data as XML httpRequest.ContentType = "text/xml" ; // string data = xmlDoc.InnerXml; byte[] bytedata = Encoding.UTF8.GetBytes(XMLRequest); // Get the request stream. Stream requestStream = httpRequest.GetRequestStream(); // Write the data to the request stream. requestStream.Write(bytedata, 0, bytedata.Length); requestStream.Close(); //Get Response HttpWebResponse httpResponse = (HttpWebResponse)httpRequest.GetResponse(); // Get the stream associated with the response. Stream receiveStream = httpResponse.GetResponseStream (); // Pipes the stream to a higher level stream reader with the required encoding format. StreamReader readStream = new StreamReader (receiveStream, Encoding.UTF8); string  ReceivedData    =   readStream.ReadToEnd (); httpResponse.Close (); readStream.Close (); return ReceivedData; } }

從 XML中提取資料

我寫了一個簡單的解析器。用于下述findNode函數的構造函數應給予原始XML資料，以及你想要找到的子節點對象。如果節點可以在最進階别的XML字元串找到，它将傳回該節點的值，如果找不到就null。這個解析器是特定于：簡單的XML-RPC，需要花點時間來解碼編碼的字元，那也很簡單。

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public string findNode(string Xml,string SearchForTag) { int     NestCounter     =   0; bool    FoundTag        =   false ; int     FoundTagLevel   =   0; string  ReturnValue     =   null ; //  Break it down by "<" string  []  TagArray    =   Xml.Split( '<' ); for (int i=0;i<TagArray.Length;i++) { if (i>175 && i<180) { int Hello=1; } string  ThisLine    =   "<" + TagArray[i]; if (ThisLine.Length <= 1)                                           continue ; if ((ThisLine.Length >= 2) && (ThisLine.Substring(0,2) == "<?" ))    continue ; if ((ThisLine.Length >= 3) && (ThisLine.Substring(0,3) == "<--" ))   continue ; //  It can be a vector or a scalar - vectors are full of scalars so we'll ThisLine                =   ThisLine.Replace( "  " , " " ); ThisLine                =   ThisLine.Replace( "</" , "</" ); string  []  FieldArray  =   ThisLine.Split(' '); bool    AddLineToResult =   FoundTag; //  Nest counter is the level we are operating on. We only check the first //  Level. When a vector is found we increase the NestCount and we won' t //  search for the ID if (NestCounter <= 1) { //  Initial array we are looking on level 1