1720
#include<stdio.h>
int main()
{
int a,b;
while(scanf("%x%x",&a,&b)!=EOF)
{
int sum=a+b;
printf("%d\n",sum);
}
return 0;
}
1062
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main()
{
int t;
scanf("%d",&t);
getchar();
while(t--)
{
char s[1010];
int t,i,j,k=0,l;
gets(s);
l=strlen(s);
for(i=0;i<l;i++)
{
k++;
if(s[i]==' ')
{
for(j=i-1;j>i-k;j--)//如果此時k==1,讓j>=i-k就會出現錯誤。
printf("%c",s[j]);
k=0;
printf(" ");
}
if(s[i+1]=='\0')
{
for(j=i;j>i-k;j--)//注意此處j!=i-k,否則會多一位。
printf("%c",s[j]);
k=0;
}
}
printf("\n");
}
system("pause");
return 0;
}
2104
#include<stdio.h>
int gcd(int n,int m)
{
int r;
while(m)
{
r=n%m;
n=m;
m=r;
}
return n;
}
int main()
{
int n,m;
while(scanf("%d%d",&n,&m)&&n!=-1||m!=-1)
{
if(gcd(n,m)==1)
printf("YES\n");
else
printf("POOR Haha\n");
}
return 0;
}
1064
#include<stdio.h>
#define max 40
__int64 dp[max];
int main()
{
int n,i,j;
dp[1]=2;
for(i=2;i<max;i++)
dp[i]=3*dp[i-1]+2;
while(scanf("%d",&n)!=EOF)
{
printf("%I64d\n",dp[n]);
}
return 0;
}
2734
#include<stdio.h>
#include<string.h>
int main()
{
char str[300];//str[]數組
int sum;
while(gets(str))
{
if(str[0]=='#')
break;
else
{ sum=0;
int l=strlen(str);
for(int i=0;i<l;i++)
{
if(str[i]==' ')//哎 一開始少了一個=,浪費時間
{
sum+=0;
}
else
{
sum+=(i+1)*(str[i]-'A'+1);
}
}
printf("%d\n",sum);
}
}
return 0;
}
1170
#include<stdio.h>
int main()
{
int t,a,b;
char c;
scanf("%d",&t);
while(t--)
{
getchar();//吸收空格
scanf("%c %d %d",&c,&a,&b);
//或者 scanf("%c%d%d",&c,&a,&b);
if(c=='+')
printf("%d\n",a+b);
else if(c=='-')
printf("%d\n",a-b);
else if(c=='*')
printf("%d\n",a*b);
else
{
if(a%b==0)
printf("%d\n",a/b);
else
printf("%.2f\n",(float)a/b);//注意要求,另加強制轉換
}
}
return 0;
}
1197
#include<stdio.h>
#include<string.h>
int judge(int i,int n)
{
int sum=0;
do
{
sum+=i%n;
i=i/n;
}while(i!=0);
return sum;
}
int main()
{
int i,j,k;
for(i=2992,j=0;i<10000;i++)
if(judge(i,10)==judge(i,12)&&judge(i,10)==judge(i,16))
printf("%d\n",i);
return 0;
}
2629
#include <iostream>
#include <string>
using namespace std;
int main()
{
int n,t;
string home,a;
cin>>n;
for(int k = 0 ; k < n ; k++)
{
cin>>a;
t = (a[0]-'0')*10+a[1]-'0';
switch(t)
{
case 11:home = "Beijing";break;
case 31:home = "Shanghai";break;
case 21:home = "Liaoning";break;
case 33:home = "Zhejiang";break;
case 54:home = "Tibet";break;
case 71:home = "Taiwan";break;
case 81:home = "Hong Kong";break;
case 82:home = "Macao";break;
default :break;
}
cout<<"He/She is from "<<home<<",and his/her birthday is on "
<<a[10]<<a[11]<<","<<a[12]<<a[13]<<","<<a[6]<<a[7]<<a[8]<<a[9]
<<" based on the table."<<endl;
}
return 0;
}