杭電1591 hdu 1591 Encoded Love-letter

Encoded Love-letter

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 1621    Accepted Submission(s): 563

Problem Description After Gardon had got Angel's letter, he found it was encoded...Oh my god, why did she encode a love-letter?? But don't worry, she wrote the algorithm for encoding after the letter:

Each charactor are changed to a corresponding charactor. If the keyword is "Angel", the rule will be:

ABCDEFGHIJKLMNOPQRSTUVWXYZ

ANGELZYXWVUTSRQPOMKJIHFDCB

You may find that in the bottom line, charactors of the keyword come first. All other charactors will come in a reversed order.

Now given another keyword, work the letter out!

Can you write a program to translate the letter?

Input The letter will begin with the keyword (All uppercase), then lines of text.  

Output Decode the letter and print it out. Please note that a upper-case charactor will be decoded to a upper-case charactor, while a lower-case charactor will be decoded to a lower-case charactor.  

Sample Input

ANGEL
Fxlr jxaj eac W xlam cqim hqwgl
W xahl kqsl kplgwat zlltwry
Tlj sl atfack jxwru W eqr'j farra zqmylj cqi
W mlslsnlm aj jxl eac
Cqi aml atfack qr sc swre
Lhlrjxqiyx W vikj gar jxwru anqij cqi
Wz jxl eac wr jxl zijiml
Jxwk tqhl fwtt nlgqswry jmil
W'hl rlhlm gxaryl sc swre jxaj W fwtt tqhl cqi zqmlhlm
W eqr'j gaml xqf zqqt wj wk
W fwtt tlj sc emlas gqsl jmil
W fwtt jltt cqi kqsljxwry W farra tlj cqi urqf, W tlj cqi urqf

W tqhl cqi, tqhwry cqi, ak jxl sqikl tqhlk jxl mwgl
Lhlr lhlmc eac xak kjqms, W fwtt atfack nc cqim kwel
W swkk cqi, swkkwry cqi
W eqr'j gaml xqf xame wj wk
W vikj farj cqi jq nl xappc
Lhlmcjxwry, W eq wj zqm cqi
        

Sample Output

When that day I hear your voice
I have some special feeling
Let me always think I don't wanna forget you
I remember at the day
You are always on my mind
Eventhough I just can think about you
If the day in the future
This love will becoming true
I've never change my mind that I will love you forever
I don't care how fool it is
I will let my dream come true
I will tell you something I wanna let you know, I let you know

I love you, loving you, as the mouse loves the rice
Even every day has storm, I will always by your side
I miss you, missing you
I don't care how hard it is
I just want you to be happy
Everything, I do it for you 
        

Author DYGG  

Source HDU “Valentines Day” Open Programming Contest 2007-02-14  

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題的意思是随便輸入一個字元串，然後密碼字元串前幾個跟輸入字元串相同，後邊是到這來，如果已經出現，就不用存了，附代碼：

#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
char sh[1100],s[1100];
char c;
int i,j,k,l,m,n;
void ac(char sh[])
{
	l=strlen(sh);
	for(i=0;i<l;i++)
	if(sh[i]>='a'&&sh[i]<='z')
	sh[i]-=32;//先變成大寫 
	for(i=0;i<l;i++)
	s[i]=sh[i];
	int flag=25;
	for(i=25;i>=0;i--)//得到密碼字元串 
	{
		for(j=0;j<l;j++)
		if('Z'-i==sh[j])
		break;
		if(j==l)
		s[flag--]='Z'-i;
	}
}
int main()
{
	scanf("%s",sh);
	getchar();
	ac(sh);
	while(scanf("%c",&c)!=EOF)//逐個字母輸入 
	{
		for(i=0;i<26;i++)
		{
			if(c==s[i])
			{
				printf("%c",'A'+i);
				break;
			}
			
			if(c==s[i]+32)
			{
				printf("%c",'a'+i);
				break;
			}
		}
			if(i==26)
			printf("%c",c);
	}
}