該樓層疑似違規已被系統折疊 隐藏此樓檢視此樓
程式如下
gama = 2*pi/9;
h = 300;
Rr = 400;
Dr = 850;
R1 = h/(2*sin(gama/2));
theta1 = linspace(0,gama/8,10);
theta2 = linspace(gama/8,gama/4,10);
theta3 = linspace(gama/4,3*gama/8,10);
theta4 = linspace(3*gama/8,gama/2,10);
theta5 = linspace(gama/2,5*gama/8,10);
theta6 = linspace(5*gama/8,3*gama/4,10);
theta7 = linspace(3*gama/4,7*gama/8,10);
theta8 = linspace(7*gama/8,gama,10);
theta = [theta1 theta2 theta3 theta4 theta5 theta6 theta7 theta8];
Y1 = -80.9186*theta1.^3+279.4697*theta1.^2-153.9023*theta1+474.3163;
Y2 = -80.9186*(theta2-gama/8).^3+258.2853*(theta2-gama/8).^2-106.7218*(theta2-gama/8)+462.9603;
Y3 = -407.0496*(theta3-gama/4).^3+237.1009*(theta3-gama/4).^2-63.7437*(theta3-gama/4)+455.5382;
Y4 = 388.6254*(theta4-3*gama/8).^3+130.5355*(theta4-3*gama/8).^2-31.6614*(theta4-3*gama/8)+451.5106;
Y5 = -388.6254*(theta5-gama/2).^3+232.2774*(theta5-gama/2).^2+450.0000;
Y6 = 407.0496*(theta6-5*gama/8).^3+130.5355*(theta6-5*gama/8).^2+31.6614*(theta6-5*gama/8)+451.5106;
Y7 = 80.9186*(theta7-3*gama/4).^3+237.1009*(theta7-3*gama/4).^2+63.7437*(theta7-3*gama/4)+455.5382;
Y8 = 80.9186*(theta8-7*gama/8).^3+258.2853*(theta8-7*gama/8).^2+106.9743*(theta8-7*gama/8)+462.9603;
c1 = -R1.*(sin(gama-theta)+sin(theta));
c2 = R1.*(cos(gama-theta)-cos(theta));
c3 = -h^2*sin(theta)./(sin(gama-theta)+sin(theta))+h^2/2-...
R1^2*sin(gama).*(cos(gama-theta)-cos(theta))./(sin(gama-theta)+sin(theta));
c5 = h.*sin(theta)./(sin(gama-theta)+sin(theta));
YY4 = [Y4(1) Y4(2) Y4(3) Y4(4) Y4(5) Y4(6) Y4(7) Y4(8) Y4(9) ceil(Y4(10))];
Y11 = [Y1 Y2 Y3 YY4];
Y22 = [Y5 Y6 Y7 Y8];
Y =[Y11 Y22];
Z1 = -sqrt(Rr^2-(Y11-Dr).^2);
Z2 = sqrt(Rr^2-(Y22-Dr).^2);
Z = [Z1 Z2];
X = -c3./c1-h./c1.*Z-c2./c1.*Y;
R1 = h/(2*sin(gama/2));
Xc = 0;
Yc = R1*sin(gama)./(sin(gama-theta)+sin(theta));
Zc = h*sin(theta)./(sin(gama-theta)+sin(theta))-h/2;
r = sqrt((X-Xc).^2+(Y-Yc).^2+(Z-Zc).^2);
plot(theta,r)
謝謝各位大哥，想要實作的就是将r繞theta軸進行旋轉，成為空間曲面