比如:現在是2004-03-26 13:31:40
過去是:2004-01-02 11:30:24
我現在要獲得兩個日期差,差的形式為:xx天xx小時xx分xx秒
方法一:
dateformat df = new simpledateformat("yyyy-mm-dd hh:mm:ss");
try
{
date d1 = df.parse("2004-03-26 13:31:40");
date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.gettime() - d2.gettime();
long days = diff / (1000 * 60 * 60 * 24);
}
catch (exception e)
方法二:
simpledateformat df = new simpledateformat("yyyy-mm-dd hh:mm:ss");
java.util.date now = df.parse("2004-03-26 13:31:40");
java.util.date date=df.parse("2004-01-02 11:30:24");
long l=now.gettime()-date.gettime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
system.out.println(""+day+"天"+hour+"小時"+min+"分"+s+"秒");
方法三:
simpledateformat dfs = new simpledateformat("yyyy-mm-dd hh:mm:ss");
java.util.date begin=dfs.parse("2004-01-02 11:30:24");
java.util.date end = dfs.parse("2004-03-26 13:31:40");
long between=(end.gettime()-begin.gettime())/1000;//除以1000是為了轉換成秒
long day1=between/(24*3600);
long hour1=between%(24*3600)/3600;
long minute1=between%3600/60;
long second1=between%60/60;
system.out.println(""+day1+"天"+hour1+"小時"+minute1+"分"+second1+"秒");
====================================================
java 比較時間大小
string s1="2008-01-25 09:12:09";
string s2="2008-01-29 09:12:11";
java.text.dateformat df=new java.text.simpledateformat("yyyy-mm-dd hh:mm:ss");
java.util.calendar c1=java.util.calendar.getinstance();
java.util.calendar c2=java.util.calendar.getinstance();
c1.settime(df.parse(s1));
c2.settime(df.parse(s2));
}catch(java.text.parseexception e){
system.err.println("格式不正确");
int result=c1.compareto(c2);
if(result==0)
system.out.println("c1相等c2");
else if(result<0)
system.out.println("c1小于c2");
else
system.out.println("c1大于c2");