我使用SAX(Simple API for XML)来解析XML文档。该文档是一个巨大的XML文件(dblp.xml - 1.46 GB)，我写了几行解析器并在小文件上测试它，它的工作原理。
Sample.XML和Student.XML是几行XML的小文件，我的解析器会解析它们但是当我更改dblp.XML的路径时，它会生成找不到文件的异常(文件仍然存在其他示例文件，但它的巨大尺寸)
这是我得到的例外：
java.io.FileNotFoundException: E:\Workspaces\Java\SaxParser\xml\dblp.dtd (The system cannot find the file specified)
这是我的代码：
package com.teamincredibles.sax;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.SAXException;
import org.xml.sax.helpers.DefaultHandler;
public class Parser extends DefaultHandler {
public void getXml() {
try {
SAXParserFactory saxParserFactory = SAXParserFactory.newInstance();
SAXParser saxParser = saxParserFactory.newSAXParser();
final MySet openingTagList = new MySet();
final MySet closingTagList = new MySet();
DefaultHandler defaultHandler = new DefaultHandler() {
public void startDocument() throws SAXException {
System.out.println("Starting Parsing...\n");
}
public void endDocument() throws SAXException {
System.out.print("\n\nDone Parsing!");
}
public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
if (!openingTagList.contains(qName)) {
openingTagList.add(qName);
System.out.print("\n");
}
}
public void characters(char ch[], int start, int length)
throws SAXException {
}
public void endElement(String uri, String localName, String qName)
throws SAXException {
if (!closingTagList.contains(qName)) {
closingTagList.add(qName);
System.out.print("" + qName + ">");
}
}
};
saxParser.parse("xml/dblp.xml", defaultHandler);
} catch (Exception e) {
e.printStackTrace();
}
}
public static void main(String args[]) {
Parser readXml = new Parser();
readXml.getXml();
}
}
我无法弄清楚的是什么。