HDOJ 1170 Balloon Comes!

       简单题，读取运算符和两个数字进行相应的计算。

#include <cstdio>

char opr[2];
//#define yangyuan
int main()
{
#ifdef yangyuan
	freopen("in", "r", stdin);
#endif
    int n, a, b;
    scanf("%d", &n);
    while (n--)
	{
		scanf("%s%d%d", opr, &a, &b);
        switch (opr[0])
        {
		case '+':
            printf("%d\n", a + b);
			break;
		case '-':
			printf("%d\n", a - b);
			break;
		case '*':
            printf("%d\n", a * b);
			break;
		case '/':
            if (a % b)
                printf("%.2f\n", (double)a / b);
			else
				printf("%d\n", a / b);
			break;
        }
	}
    return 0;
}