c语言字符串转成ascii码,c语言-显示字符串每一个字符的ascii码问题

#include

#include

int main() {

char str[]="";

int i=0;

int count=0;

printf("please input your words:");

scanf("%s",&str);

printf("you have input the words %s\n",str);

printf("you have input the words %c\n",str[1]);

printf("you have input the words %c\n",str[2]);

printf("you have input the words %c\n",str[3]);

int length=strlen(str);

for(i=0;i

int num=str[i];

printf("number %d,",num);

printf("character %c,",str[i]);

printf("i=%d\n",i);

}

}

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这段程序输入字符串1234后，会显示

you have input the words 1234

you have input the words 2

you have input the words 3

you have input the words 4

number 49,character 1,i=0

number 1,character ,i=1

number 0,character ,i=2

number 0,character ,i=3

我想它能显示每个字符的ascii码，求各位高手指点