魔法数字Magic Number C语言代码

题目描述：

如果一个数（可能包含前导0）乘以2，如142857*2=285714，

依然由原来的数字组成的话，这样的数(142857)就叫Magic Number

输入：

多组测试数据，每组一行，每行是一个不大于1e10000整数（可能有前导0），

遇到EOF标志结束程序

输出：

判断这个数是不是Magic Number，是的话输出“Magic Number”

否则输出“Not Magic Number”

样例输入：

142857

0142857

857142

0588235294117647

样例输出：

Magic Number

Magic Number

Not Magic Number

Magic Number

难度：Very Easy

CODE:

#include <stdio.h>

#include <string.h>

#define MAX 10001

typedef struct {

int date[MAX];

int len;

}BigInt;

int magic(BigInt a,int m);

int main() {

char str[MAX];

BigInt a;

int i,len;

while ( scanf("%s",str) != EOF ) {

len = strlen(str);

for ( i = 0; i < len; i++ ) {

a.date[len-i-1] = str[i] - '0';

}

a.len = len;

if ( magic(a,2) ) {

printf("Magic Number\n");

} else {

printf("Not Magic Number\n");

}

}

return 0;

}

int magic(BigInt a,int m) {

int i,temp;

int carry = 0;

int s[10],e[10];

for( i = 0; i < 10; i++ ) {

s[i] = e[i] = 0;

}

for ( i = 0; i < a.len; i++ ) {

s[a.date[i]] ++;

}

for ( i = 0; i < a.len; i ++ ) {

temp = a.date[i] * m + carry;

e[temp%10] ++;

carry = temp / 10;

}

if ( carry ) {

e[carry] ++;

}

for ( i = 0; i < 10; i++ ) {

if ( s[i] != e[i] ) {

return 0;

}

}

return 1;

}

CODE1:

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

int main() {

int a[10005],old[10],mulold[10];

memset(old,0,sizeof(old));

memset(mulold,0,sizeof(mulold));

char c;

int i=0,j,k,bit=0,number=0;

bool flag=true;

for (;scanf("%c",&c)!=EOF;i=0,bit=0,number=0,flag=true) {

//scanf("%c",&c);

while(c!='\n') {

a[i]=c-'0';

old[c-'0']=1;

i++;

scanf("%c",&c);

}

//for(j=0;j<i;j++) printf("%d ",a[j]);

for(j=0;j<i;j++) {

int tmp=a[i-1-j]*2+bit;

//printf("tmp:%d ",tmp);

if(j==i-1&&tmp>=10) {

if(old[tmp/10]==0)

{

printf("*Not Magic Number \n");

flag=false;

break;

}

mulold[tmp/10]=1;

}

if(old[tmp%10]==0)

{

printf("*Not Magic Number \n");

flag=false;

break;

}

mulold[tmp%10]=1;

bit=tmp/10;

}

//for(k=0;k<10;k++) {printf("%d ",old[k]);printf("%d\n",mulold[k]);}

if(flag) {

for(k=0;k<10;k++)

if(old[k]!=mulold[k]) {

printf("Not Magic Number \n");

break;

}

if(k==10)

printf("Magic Number \n");

}

memset(old,0,sizeof(old));

memset(mulold,0,sizeof(mulold));

}

return 0;

}

CODE2:

#include <stdio.h>

#include <stdlib.h>

#include <string.h>

int main() {

int a[10005],old[10],mulold[10];

memset(old,0,sizeof(old));

memset(mulold,0,sizeof(mulold));

char c;

int i=0,j,k,bit=0,number=0;

bool flag=true;

for (;scanf("%c",&c)!=EOF;i=0,bit=0,number=0,flag=true) {

//scanf("%c",&c);

while(c!='\n') {

a[i]=c-'0';

old[c-'0']=1;

i++;

scanf("%c",&c);

}

//for(j=0;j<i;j++) printf("%d ",a[j]);

for(j=0;j<i;j++) {

int tmp=a[i-1-j]*2+bit;

//printf("tmp:%d ",tmp);

if(j==i-1&&tmp>=10) {

if(old[tmp/10]==0)

{

printf("Not Magic Number \n");

flag=false;

break;

}

mulold[tmp/10]=1;

}

if(old[tmp%10]==0)

{

printf("*Not Magic Number \n");

flag=false;

break;

}

mulold[tmp%10]=1;

bit=tmp/10;

}

//for(k=0;k<10;k++) {printf("%d ",old[k]);printf("%d\n",mulold[k]);}

if(flag) {

for(k=0;k<10;k++)

if(old[k]!=mulold[k]) {

printf("Not Magic Number \n");

break;

}

if(k==10)

printf("Magic Number \n");

}

memset(old,0,sizeof(old));

memset(mulold,0,sizeof(mulold));

}

return 0;

}