http://acm.hdu.edu.cn/showproblem.php?pid=2097
解法同1197,输出有些不一样而已
View Code
1 #include <stdio.h>
2 int main()
3 {
4 int i, n, sum10, sum12, sum16,a[10000];
5 for (i=1000; i<10000; i++){
6 n = i;
7 sum10 = 0;
8 while (n){
9 sum10 += n%10;
10 n /= 10;
11 }
12 n = i;
13 sum12 = 0;
14 while (n){
15 sum12 += n%12;
16 n /= 12;
17 }
18 n = i;
19 sum16 = 0;
20 while (n){
21 sum16 += n%16;
22 n /= 16;
23 }
24 if (sum10==sum12 && sum12==sum16)
25 a[i]=1;
26 else a[i]=0;
27 }
28 while(scanf("%d",&n)&&n)
29 if(a[n])
30 printf("%d is a Sky Number.\n",n);
31 else printf("%d is not a Sky Number.\n",n);
32 return 0;
33 }
转载于:https://www.cnblogs.com/huzhenbo113/archive/2013/04/09/3011308.html