Q143 - Q145 Exams/2014 q3bfsm / Exams/2014 q3c / Exams/m2014 q6b

这几道题都比较简单，都是看图写代码，快速过一遍

Q143 Exams/2014 q3bfsm

题目链接：Exams/2014 q3bfsm - HDLBits (01xz.net)

代码如下：

module top_module (
    input clk,
    input reset,   // Synchronous reset
    input x,
    output z
);

    parameter A = 3'b000;
    parameter B = 3'b001;
    parameter C = 3'b010;
    parameter D = 3'b011;
    parameter E = 3'b100;
    
    reg [2:0]	curr_state;
    reg	[2:0]	next_state;
    
    always @(posedge clk) begin
        if(reset) begin
           curr_state <= A; 
        end
        else begin
           curr_state <= next_state; 
        end
    end
    
    always @(*) begin
        case(curr_state)
            A:next_state = x ? B : A;
            B:next_state = x ? E : B;
            C:next_state = x ? B : C;
            D:next_state = x ? C : B;
            E:next_state = x ? E : D;
            default: next_state = A;
        endcase
    end
    
    assign z = (curr_state == D)||(curr_state == E);
    
endmodule
           

Q144 Exams/2014 q3c

 题目链接：Exams/2014 q3c - HDLBits (01xz.net)

代码如下：

module top_module (
    input clk,
    input [2:0] y,
    input x,
    output Y0,
    output z
);

    always @(*) begin
        case(y)
            3'b000: Y0 = x;
            3'b001: Y0 = ~x;
            3'b010: Y0 = x;
            3'b011: Y0 = ~x;
            3'b100: Y0 = ~x;
            default: Y0 = 1'b0;
        endcase
    end
    
    assign z = (y == 3'b011)||(y == 3'b100);
endmodule
           

Q145 Exams/m2014 q6b

题目链接：Exams/m2014 q6b - HDLBits (01xz.net)

代码如下：

module top_module (
    input [3:1] y,
    input w,
    output Y2);

    always @(*) begin
        case(y)
            3'b000: Y2 = 1'b0;
            3'b001: Y2 = 1'b1;
            3'b010: Y2 = w;
            3'b011: Y2 = 1'b0;
            3'b100: Y2 = w;
            3'b101: Y2 = 1'b1;
            default: Y2 = 1'b0;
        endcase
    end
   
endmodule