天天看点

杭电OJ 2029(C++)

Palindromes _easy version

#include<iostream>
using namespace std;
#include<string>

int main()
{
	int n,j,i;
	string a;
	cin>>n;
	for(j = 0 ; j < n ; j++)
	{
		int k = 0;
		cin>>a;
		for(i = 0 ; i < a.size()/2 ; i++)
		{
			if(a[i] == a[a.size()-1-i])
				k++;
		}
		if(k == a.size()/2)
				cout<<"yes"<<endl;
			else
				cout<<"no"<<endl;
	}
	return 0;
}
           

继续阅读