如果隻有插入的話,直接維護線性基就好了
但是現在有了删除,我們按時間分治,将操作建立成一個線段樹。每一個數都有一個存活的區間,我們線上段樹上更新這個區間。然後dfs線段樹。線段樹上每個節點維護的是到當這個節點的線性基。然後就可以免去删除操作了
具體見代碼
#include<vector>
#include<map>
#include<stack>
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
const int maxn = ;
vector<int> oper[maxn * ];
#define root 1,n
#define lson l,m
#define rson m+1,r
#define Mid int m = (l + r) >> 1
#define Now int l,int r
int ID(int l, int r) {
return l + r | (l != r);
}
void insert(Now,int il,int ir,int v){
int o = ID(l,r);
if(il <= l && r <= ir){
oper[o].push_back(v);
return;
}
Mid;
if(il <= m) insert(lson,il,ir,v);
if(m+<=ir) insert(rson,il,ir,v);
}
struct Info{
int bas[];
void init(){
memset(bas,,sizeof(bas));
}
void add(int x){
for(int i = ;i>=;i--) {
if((x>>i)&) {
if(bas[i]) x^=bas[i];
else {
bas[i]=x;
break;
}
}
}
}
int que(){
int ans = ;
for(int i = ;i>=;i--) ans = max(ans,ans^bas[i]);
return ans;
}
void cpy(Info & v){
for(int i = ; i <= ; i ++){
bas[i] = v.bas[i];
}
}
}info[];
int nex[],head,tail;
void init(){
head = ,tail = -;
for(int i = ; i < ; i ++)
nex[i] = i + ;
nex[tail] = -;
}
int newInfo(){
info[head].init();
int ret = head;
head = nex[head];
return ret;
}
void deleteInfo(int st){
nex[tail] = st;
nex[st] = -;
tail = st;
}
stack<int> S;
void dfs(Now){
int o = ID(l,r),st = newInfo();
info[st].cpy(info[S.top()]);
S.push(st);
for(vector<int>::iterator it = oper[o].begin(); it != oper[o].end();it++)
info[st].add(*it);
if(l == r) printf("%d\n",info[st].que());
else{
Mid;
dfs(lson),dfs(rson);
}
deleteInfo(st);
S.pop();
}
map<int,int> M;
int main(){
int n;
scanf("%d",&n);
int x;
for(int i = ; i <= n ; i ++){
scanf("%d",&x);
if(x > ) M[x] = i;
else{
insert(root,M[-x],i-,-x);
M.erase(-x);
}
}
for(map<int,int>::iterator ite = M.begin();ite != M.end();ite++)
insert(root,ite->second,n,ite->first);
init();
int rot = newInfo();
S.push(rot);
dfs(root);
return ;
}