程設作業（合成矩形）

Give you N rectangles.If you can pick exactly three pieces of those rectangles to form a larger rectangle?

input:

There are several testcases.

The first line is an integer T, indicating the number of testcases.

For each testcase:

The first line is a integer N and N is no more than 10.

The second line contains 2*N integers describing N rectangles.Each rectangle is described by 2 integers indicating as width and height.

All these integers in the second line are between [1,10000]

output

If you can do it, print Yes.Otherwise, print No instead.

sample input
2
4
1 1 1 1 1 2 2 2
4
1 1 2 2 10 10 20 20

sample output
Yes
No
           

答案：

#include<stdio.h>
int Findequal(int origin, int *a, int num) {
  int i, count = ;
  for (i = ; i < num;) {
    if (origin == a[i]) {
      count++;
      i = i + ;
    }
    else if (origin != a[i])
      ++i;
  }
  return count;
}

int main(void) {
  int T, i, j;
  scanf("%d", &T);
  while (T--) {
    int N;
    scanf("%d", &N);
    int a[] = {};
    for (i = ; i <  * N; ++i)
      scanf("%d", &a[i]);

    for (i = ; i <  * N; ++i) {
      if (Findequal(a[i], a, N) >= ) {
        printf("Yes\n");
        break;
      }

      else if (Findequal(a[i], a, N) == ) {
        for (j = ; j <  * N; ++j) {
          if ( * a[i] == a[j]) {
            printf("Yes\n");
            break;
          }
        }
        break;
      }
    }
    if (i ==  * N)
      printf("No\n");
  }
  return ;
}