這個問題雖然看起來很小,卻并不那麼容易回答。
大家如果有更好的方法歡迎賜教,先來一個天真的估算方法:
假設要求一個系統的TPS(Transaction Per Second或者Task Per Second)至少為20,然後假設每個Transaction由一個線程完成,繼續假設平均每個線程處理一個Transaction的時間為4s。
那麼問題轉化為:如何設計線程池大小,使得可以在1s内處理完20個Transaction?
計算過程很簡單,每個線程的處理能力為0.25TPS,那麼要達到20TPS,顯然需要20/0.25=80個線程。
很顯然這個估算方法很天真,因為它沒有考慮到CPU數目。一般伺服器的CPU核數為16或者32,如果有80個線程,那麼肯定會帶來太多不必要的線程上下文切換開銷。
再來第二種簡單的但不知是否可行的方法(N為CPU總核數):
如果是CPU密集型應用,則線程池大小設定為N+1
如果是IO密集型應用,則線程池大小設定為2N+1
如果一台伺服器上隻部署這一個應用并且隻有這一個線程池,那麼這種估算或許合理,具體還需自行測試驗證。
接下來在這個文檔:伺服器性能IO優化 中發現一個估算公式:
最佳線程數目 = ((線程等待時間+線程CPU時間)/線程CPU時間 )* CPU數目
比如平均每個線程CPU運作時間為0.5s,而線程等待時間(非CPU運作時間,比如IO)為1.5s,CPU核心數為8,那麼根據上面這個公式估算得到:((0.5+1.5)/0.5)*8=32。這個公式進一步轉化為:
最佳線程數目 = (線程等待時間與線程CPU時間之比 + 1)* CPU數目
可以得出一個結論:線程等待時間所占比例越高,需要越多線程。線程CPU時間所占比例越高,需要越少線程。
上一種估算方法也和這個結論相合。
一個系統最快的部分是CPU,是以決定一個系統吞吐量上限的是CPU。增強CPU處理能力,可以提高系統吞吐量上限。但根據短闆效應,真實的系統吞吐量并不能單純根據CPU來計算。那要提高系統吞吐量,就需要從“系統短闆”(比如網絡延遲、IO)着手:
盡量提高短闆操作的并行化比率,比如多線程下載下傳技術
增強短闆能力,比如用NIO替代IO
第一條可以聯系到Amdahl定律,這條定律定義了串行系統并行化後的加速比計算公式:
加速比=優化前系統耗時 / 優化後系統耗時
加速比越大,表明系統并行化的優化效果越好。Addahl定律還給出了系統并行度、CPU數目和加速比的關系,加速比為Speedup,系統串行化比率(指串行執行代碼所占比率)為F,CPU數目為N:
當N足夠大時,串行化比率F越小,加速比Speedup越大。
寫到這裡,我突然冒出一個問題。
是否使用線程池就一定比使用單線程高效呢?
答案是否定的,比如Redis就是單線程的,但它卻非常高效,基本操作都能達到十萬量級/s。從線程這個角度來看,部分原因在于:
多線程帶來線程上下文切換開銷,單線程就沒有這種開銷
鎖
當然“Redis很快”更本質的原因在于:Redis基本都是記憶體操作,這種情況下單線程可以很高效地利用CPU。而多線程适用場景一般是:存在相當比例的IO和網絡操作。
是以即使有上面的簡單估算方法,也許看似合理,但實際上也未必合理,都需要結合系統真實情況(比如是IO密集型或者是CPU密集型或者是純記憶體操作)和硬體環境(CPU、記憶體、硬碟讀寫速度、網絡狀況等)來不斷嘗試達到一個符合實際的合理估算值。
最後來一個“Dark Magic”估算方法(因為我暫時還沒有搞懂它的原理),使用下面的類:
package threadpool;
import java.math.BigDecimal;
import java.math.RoundingMode;
import java.util.Timer;
import java.util.TimerTask;
import java.util.concurrent.BlockingQueue;
/**
* A class that calculates the optimal thread pool boundaries. It takes the
* desired target utilization and the desired work queue memory consumption as
* input and retuns thread count and work queue capacity.
*
* @author Niklas Schlimm
*/
public abstract class PoolSizeCalculator {
/**
* The sample queue size to calculate the size of a single {@link Runnable}
* element.
*/
private final int SAMPLE_QUEUE_SIZE = 1000;
/**
* Accuracy of test run. It must finish within 20ms of the testTime
* otherwise we retry the test. This could be configurable.
*/
private final int EPSYLON = 20;
/**
* Control variable for the CPU time investigation.
*/
private volatile boolean expired;
/**
* Time (millis) of the test run in the CPU time calculation.
*/
private final long testtime = 3000;
/**
* Calculates the boundaries of a thread pool for a given {@link Runnable}.
*
* @param targetUtilization the desired utilization of the CPUs (0 <= targetUtilization <= * 1) * @param targetQueueSizeBytes * the desired maximum work queue size of the thread pool (bytes)
*/
protected void calculateBoundaries(BigDecimal targetUtilization, BigDecimal targetQueueSizeBytes) {
calculateOptimalCapacity(targetQueueSizeBytes);
Runnable task = creatTask();
start(task);
start(task); // warm up phase
long cputime = getCurrentThreadCPUTime();
start(task); // test intervall
cputime = getCurrentThreadCPUTime() - cputime;
long waittime = (testtime * 1000000) - cputime;
calculateOptimalThreadCount(cputime, waittime, targetUtilization);
}
private void calculateOptimalCapacity(BigDecimal targetQueueSizeBytes) {
long mem = calculateMemoryUsage();
BigDecimal queueCapacity = targetQueueSizeBytes.divide(new BigDecimal(mem),
RoundingMode.HALF_UP);
System.out.println("Target queue memory usage (bytes): "
+ targetQueueSizeBytes);
System.out.println("createTask() produced " + creatTask().getClass().getName() + " which took " + mem + " bytes in a queue");
System.out.println("Formula: " + targetQueueSizeBytes + " / " + mem);
System.out.println("* Recommended queue capacity (bytes): " + queueCapacity);
}
/**
* Brian Goetz' optimal thread count formula, see 'Java Concurrency in
* * Practice' (chapter 8.2) *
* * @param cpu
* * cpu time consumed by considered task
* * @param wait
* * wait time of considered task
* * @param targetUtilization
* * target utilization of the system
*/
private void calculateOptimalThreadCount(long cpu, long wait,
BigDecimal targetUtilization) {
BigDecimal waitTime = new BigDecimal(wait);
BigDecimal computeTime = new BigDecimal(cpu);
BigDecimal numberOfCPU = new BigDecimal(Runtime.getRuntime()
.availableProcessors());
BigDecimal optimalthreadcount = numberOfCPU.multiply(targetUtilization)
.multiply(new BigDecimal(1).add(waitTime.divide(computeTime,
RoundingMode.HALF_UP)));
System.out.println("Number of CPU: " + numberOfCPU);
System.out.println("Target utilization: " + targetUtilization);
System.out.println("Elapsed time (nanos): " + (testtime * 1000000));
System.out.println("Compute time (nanos): " + cpu);
System.out.println("Wait time (nanos): " + wait);
System.out.println("Formula: " + numberOfCPU + " * "
+ targetUtilization + " * (1 + " + waitTime + " / "
+ computeTime + ")");
System.out.println("* Optimal thread count: " + optimalthreadcount);
}
/**
* * Runs the {@link Runnable} over a period defined in {@link #testtime}.
* * Based on Heinz Kabbutz' ideas
* * (http://www.javaspecialists.eu/archive/Issue124.html).
* *
* * @param task
* * the runnable under investigation
*/
public void start(Runnable task) {
long start = 0;
int runs = 0;
do {
if (++runs > 5) {
throw new IllegalStateException("Test not accurate");
}
expired = false;
start = System.currentTimeMillis();
Timer timer = new Timer();
timer.schedule(new TimerTask() {
public void run() {
expired = true;
}
}, testtime);
while (!expired) {
task.run();
}
start = System.currentTimeMillis() - start;
timer.cancel();
} while (Math.abs(start - testtime) > EPSYLON);
collectGarbage(3);
}
private void collectGarbage(int times) {
for (int i = 0; i < times; i++) {
System.gc();
try {
Thread.sleep(10);
} catch (InterruptedException e) {
Thread.currentThread().interrupt();
break;
}
}
}
/**
* Calculates the memory usage of a single element in a work queue. Based on
* Heinz Kabbutz' ideas
* (http://www.javaspecialists.eu/archive/Issue029.html).
*
* @return memory usage of a single {@link Runnable} element in the thread
* pools work queue
*/
public long calculateMemoryUsage() {
BlockingQueue queue = createWorkQueue();
for (int i = 0; i < SAMPLE_QUEUE_SIZE; i++) {
queue.add(creatTask());
}
long mem0 = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
long mem1 = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
queue = null;
collectGarbage(15);
mem0 = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
queue = createWorkQueue();
for (int i = 0; i < SAMPLE_QUEUE_SIZE; i++) {
queue.add(creatTask());
}
collectGarbage(15);
mem1 = Runtime.getRuntime().totalMemory() - Runtime.getRuntime().freeMemory();
return (mem1 - mem0) / SAMPLE_QUEUE_SIZE;
}
/**
* Create your runnable task here.
*
* @return an instance of your runnable task under investigation
*/
protected abstract Runnable creatTask();
/**
* Return an instance of the queue used in the thread pool.
*
* @return queue instance
*/
protected abstract BlockingQueue createWorkQueue();
/**
* Calculate current cpu time. Various frameworks may be used here,
* depending on the operating system in use. (e.g.
* http://www.hyperic.com/products/sigar). The more accurate the CPU time
* measurement, the more accurate the results for thread count boundaries.
*
* @return current cpu time of current thread
*/
protected abstract long getCurrentThreadCPUTime();
}
然後自己繼承這個抽象類并實作它的三個抽象方法,比如下面是我寫的一個示例(任務是請求網絡資料),其中我指定期望CPU使用率為1.0(即100%),任務隊列總大小不超過100,000位元組:
package threadpool;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.lang.management.ManagementFactory;
import java.math.BigDecimal;
import java.net.HttpURLConnection;
import java.net.URL;
import java.util.concurrent.BlockingQueue;
import java.util.concurrent.LinkedBlockingQueue;
public class SimplePoolSizeCaculatorImpl extends PoolSizeCalculator {
@Override
protected Runnable creatTask() {
return new AsyncIOTask();
}
@Override
protected BlockingQueue createWorkQueue() {
return new LinkedBlockingQueue(1000);
}
@Override
protected long getCurrentThreadCPUTime() {
return ManagementFactory.getThreadMXBean().getCurrentThreadCpuTime();
}
public static void main(String[] args) {
PoolSizeCalculator poolSizeCalculator = new SimplePoolSizeCaculatorImpl();
poolSizeCalculator.calculateBoundaries(new BigDecimal(1.0), new BigDecimal(100000));
}
}
/**
* 自定義的異步IO任務
* @author Will
*
*/
class AsyncIOTask implements Runnable {
public void run() {
HttpURLConnection connection = null;
BufferedReader reader = null;
try {
String getURL = "http://baidu.com";
URL getUrl = new URL(getURL);
connection = (HttpURLConnection) getUrl.openConnection();
connection.connect();
reader = new BufferedReader(new InputStreamReader(
connection.getInputStream()));
String line;
while ((line = reader.readLine()) != null) {
// empty loop
}
}
catch (IOException e) {
} finally {
if(reader != null) {
try {
reader.close();
}
catch(Exception e) {
}
}
connection.disconnect();
}
}
}
得到如下輸出:
Target queue memory usage (bytes): 100000
createTask() produced threadpool.AsyncIOTask which took 40 bytes in a queue
Formula: 100000 / 40
* Recommended queue capacity (bytes): 2500
Number of CPU: 8
Target utilization: 1
Elapsed time (nanos): 3000000000
Compute time (nanos): 280801800
Wait time (nanos): 2719198200
Formula: 8 * 1 * (1 + 2719198200 / 280801800)
* Optimal thread count: 88
推薦的任務隊列大小為2500,線程數為88。依次為依據,我們就可以構造這樣一個線程池:
ThreadPoolExecutor pool = new ThreadPoolExecutor(88, 88, 0L, TimeUnit.MILLISECONDS, new LinkedBlockingQueue<Runnable>(2500));
可以将這個檔案打包成可執行的jar檔案,這樣就可以拷貝到測試/正式環境上執行。
<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>threadpool</groupId>
<artifactId>dark-magic</artifactId>
<version>1.0-SNAPSHOT</version>
<packaging>jar</packaging>
<name>dark_magic</name>
<url>http://maven.apache.org</url>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
</properties>
<dependencies>
</dependencies>
<build>
<finalName>dark-magic</finalName>
<plugins>
<plugin>
<artifactId>maven-assembly-plugin</artifactId>
<configuration>
<appendAssemblyId>false</appendAssemblyId>
<descriptorRefs>
<descriptorRef>jar-with-dependencies</descriptorRef>
</descriptorRefs>
<archive>
<manifest>
<!-- 此處指定main方法入口的class -->
<mainClass>threadpool.SimplePoolSizeCaculatorImpl</mainClass>
</manifest>
</archive>
</configuration>
<executions>
<execution>
<id>make-assembly</id>
<phase>package</phase>
<goals>
<goal>assembly</goal>
</goals>
</execution>
</executions>
</plugin>
</plugins>
</build>
</project>
來源:
www.cnblogs.com/cjsblog/p/9068886.html
參考:
http://ifeve.com/how-to-calculate-threadpool-size/\ http://www.importnew.com/17384.html\ https://www.cnblogs.com/cherish010/p/8334952.html近期熱文推薦:
1.Java 15 正式釋出, 14 個新特性,重新整理你的認知!!
2.終于靠開源項目弄到 IntelliJ IDEA 激活碼了,真香!
3.我用 Java 8 寫了一段邏輯,同僚直呼看不懂,你試試看。。
4.吊打 Tomcat ,Undertow 性能很炸!!
5.《Java開發手冊(嵩山版)》最新釋出,速速下載下傳!
覺得不錯,别忘了随手點贊+轉發哦!