1.复制一个\member\ajax_loginsta.php文件并将其新命名为ajax_loginuser.php（该页面就是后面调用的样式，你的css或者需要调用的信息就在此文件里面修改）我这里只用头像和退出功能，我的ajax_loginuser.php是这样的。如果你是同样的需求可以直接复制过去。
<?php
define('AJAXLOGIN', TRUE);
require_once(dirname(__FILE__)."/config.php");
AjaxHead();
if($myurl == '') exit('');
$uid = $cfg_ml->M_LoginID;
!$cfg_ml->fields['face'] && $face = ($cfg_ml->fields['sex'] == '女')? 'dfgirl' : 'dfboy';
$facepic = empty($face)? $cfg_ml->fields['face'] : $GLOBALS['cfg_memberurl'].'/templets/images/'.$face.'.png';
?>
<div class="userinfo">
<div class="userface">
<a href="<?php echo $cfg_memberurl; ?>/index.php"><img src="<?php echo $facepic;?>" width="52" height="52" /></a>
<a href="<?php echo $cfg_memberurl; ?>/index_do.php?fmdo=login&dopost=exit">退出登录</a>
</div>
</div>
</div> 2.进入你要调用的页面，在 <head>
<head>
<script language="javascript" src="/include/dedeajax2.js"></script>
<script language="javascript" type="text/javascript">
function CheckInfo(){
var taget_obj = document.getElementById('_userinfo');
myajax = new DedeAjax(taget_obj,false,false,'','','');
myajax.SendGet2("/member/ajax_loginuser.php");
DedeXHTTP = null;
}
</script> 然后在 <body>
<body>
<div id="_userinfo">
<img onerror="CheckInfo();" src=""/>
</div> ![javascript的for (var i in data)慎用javascript中的for (var i in data)谨慎用[图]](data:image/gif;base64,R0lGODlhAQABAIAAAP///wAAACwAAAAAAQABAAACAkQBADs=)