题目链接:http://acm.njupt.edu.cn/acmhome/problemdetail.do?&method=showdetail&id=1080
题目描述有问题
1.注意最后的多余空格并没有;
2.注意每个人要不然不说,要不然只能说两次,见第二个样例,所以题目中的“至多”说法有错;
代码如下:
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
int talk[],be_talk[];
int main()
{
int T;
scanf("%d",&T);
while(T--)
{
memset(talk,,sizeof(talk));
memset(be_talk,,sizeof(be_talk));
int n,t,m;
scanf("%d%d%d",&n,&t,&m);
for(int i=;i<m;i++)
{
int p,q;
scanf("%d%d",&p,&q);
talk[p]++;
be_talk[q]++;
}
bool flag = true;
be_talk[t] = ;
for(int i=;i<m;i++)
{
if( (talk[i]!= && talk[i]!=) || be_talk[i] != ) //要么不说,要么说两次,被告诉必为一次
{
flag = false;
break;
}
}
if(flag)
printf("Success\n");
else
printf("Failure\n");
}
return ;
}