Leetcode58-最后一个单词的长度
![](https://img.laitimes.com/img/_0nNw4CM6IyYiwiM6ICdiwiIyVGduV2YfNWawNiNx8FesU2cfdGLwczX0xiRGZkRGZ0Xy9GbvNGLwIzXlpXazxyXTlVNMFXS2kVaZVTQClGVF5UMR9Fd4VGdsATNfd3bkFGazxycykFaKdkYzZUbapXNXlleSdVY2pESa9VZwlHdssmch1mclRXY39CXldWYtlWPzNXZj9mcw1ycz9WL49zZuBnLkRmM5YmM0QWYkRDN4MDOhRGZyQjZiBTN0IjNlZWOlhzLc52YucWbp5GZzNmLn9Gbi1yZtl2Lc9CX6MHc0RHaiojIsJye.png)
思路:
代码:
class Solution:
def lengthOfLastWord(self, s: str) -> int:
end = len(s)-1
while end >= 0 and s[end] == ' ':
end-=1
start = end
while start >= 0 and s[start] != ' ':
start-=1
return end-start