DateTime.Now.ToString 中的參數問題

DateTime.Now.ToString根據參數不同輸出不同内容，功能很強的，總結一下。

[C#] 

using System;

using System.Globalization;

public class MainClass { 

   public static void Main(string[] args)  {

       DateTime dt = DateTime.Now;

       String[] format = {

           "d", "D",

           "f", "F",

           "g", "G",

           "m",

           "r",

           "s",

           "t", "T",

           "u", "U",

           "y",

           "dddd, MMMM dd yyyy",

           "ddd, MMM d \"'\"yy",

           "dddd, MMMM dd",

           "M/yy",

           "dd-MM-yy",

       };

       String date;

       for (int i = 0; i < format.Length; i++) {

           date = dt.ToString(format[i], DateTimeFormatInfo.InvariantInfo);

           Console.WriteLine(String.Concat(format[i], " :" , date));

       }

  /** Output.

   *

   * d :08/17/2000

   * D :Thursday, August 17, 2000

   * f :Thursday, August 17, 2000 16:32

   * F :Thursday, August 17, 2000 16:32:32

   * g :08/17/2000 16:32

   * G :08/17/2000 16:32:32

   * m :August 17

   * r :Thu, 17 Aug 2000 23:32:32 GMT

   * s :2000-08-17T16:32:32

   * t :16:32

   * T :16:32:32

   * u :2000-08-17 23:32:32Z

   * U :Thursday, August 17, 2000 23:32:32

   * y :August, 2000

   * dddd, MMMM dd yyyy :Thursday, August 17 2000

   * ddd, MMM d "'"yy :Thu, Aug 17 '00

   * dddd, MMMM dd :Thursday, August 17

   * M/yy :8/00

   * dd-MM-yy :17-08-00

   */

   }

}

本文轉自Jack Niu部落格園部落格，原文連結：http://www.cnblogs.com/skywind/archive/2007/12/06/984897.html，如需轉載請自行聯系原作者