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Codeforces Round #320 (Div. 2) [Bayan Thanks-Round] C C Problem about Polyline 數學

                                                                       C. A Problem about Polyline                                                                                time limit per test                                                                                 1 second                                                                                memory limit per test                                                                                   256 megabytes  

There is a polyline going through points (0, 0) – (x, x) – (2x, 0) – (3x, x) – (4x, 0) – ... - (2kx, 0) – (2kx + x, x) – ....

We know that the polyline passes through the point (a, b). Find minimum positive value x such that it is true or determine that there is no such x.

Input

Only one line containing two positive integers a and b (1 ≤ a, b ≤ 109).

Output

Output the only line containing the answer. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 9. If there is no such x then output  - 1 as the answer.

Sample test(s) Input

3 1      

Output

1.000000000000      

Input

1 3      

Output

-1      

Input

4 1      

Output

1.250000000000      

  題解:對于a<b就是-1        隻有兩種情況:            上升段:a-2*ans*m=b;最小的ans是b是以m<=(a-b)/(2*b);可以得到ans的最小值  

轉載于:https://www.cnblogs.com/zxhl/p/4816083.html