上个星期学习了下金字塔的绘制,然后这周有看了看正方体的绘制,通过依次绘制6个面来绘制正方体,整体代码跟上次的金三角没有区别,只是坐标点,颜色,已经绘制的代码有点区别,上代码看看
//这是坐标
private static float[][] cubevertexcoords = new float[][] {
new float[] { // top
1, 1,-1,
-1, 1,-1,
-1, 1, 1,
1, 1, 1
},
new float[] { // bottom
1,-1, 1,
-1,-1, 1,
-1,-1,-1,
1,-1,-1
new float[] { // front
1, 1, 1,
1,-1, 1
new float[] { // back
1,-1,-1,
1, 1,-1
new float[] { // left
-1,-1, 1
new float[] { // right
};
//这是颜色
private static float[] cubecolors = new float[] {
0,1,0,1,
1,0.5f,0,1,
1,0,0,1,
1,1,0,1,
0,0,1,1,
1,0,1,1
然后必须要把呀转化为floatbuffer ,这样就可以使用了
private static floatbuffer[] cubevertexbfr;
private static floatbuffer cubecolorbfr;
转化我写了个转化的工具类
public class bufferutil {
private static floatbuffer floatbuffer;
public static floatbuffer floattobuffer(float[] f){
bytebuffer buffer =bytebuffer.allocatedirect(f.length*4);
buffer.order(byteorder.nativeorder());
floatbuffer =buffer.asfloatbuffer();
floatbuffer.put(f);
floatbuffer.position(0);
return floatbuffer;
}
下边是绘制的代码
gl.glenableclientstate(gl10.gl_vertex_array);//在上边打开在下边就要关闭,这个原因是然后边的绘制不会复用前边的颜色等的样式
gl.glenableclientstate(gl10.gl_color_array);
for (int i = 0; i < 6; i++) // draw each face
{
gl.glvertexpointer(3, gl10.gl_float, 0, cubevertexbfr[i]);
gl.glcolorpointer(4, gl10.gl_float, 0, cubecolorbfr);
gl.gldrawarrays(gl10.gl_triangle_fan, 0, 4);
gl.gldisableclientstate(gl10.gl_vertex_array);
gl.gldisableclientstate(gl10.gl_color_array);