判斷字元串是否為ip
法1:
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <errno.h>
int if_a_string_is_a_valid_ipv4_address(const char *str)
{
struct in_addr addr;
int ret;
ret = inet_pton(AF_INET, str, &addr);
if (ret > 0)
fprintf(stderr, "\"%s\" is a valid IPv4 address\n", str);
else if (ret < 0)
fprintf(stderr, "EAFNOSUPPORT: %s\n", strerror(errno));
else
fprintf(stderr, "\"%s\" is not a valid IPv4 address\n", str);
return ret;
}
int inet_pton(int family, const char *strptr, void *addrptr);
傳回:1—成功;0—輸入不是有效的表達格式,-1—出錯。
法2:
#include <stdio.h>
#include <string.h>
int a,b,c,d;
char t;
char s[100];
void main() {
strcpy(s,"123.1.2.3.1111");
if (4==sscanf(s,"%d.%d.%d.%d%c",&a,&b,&c,&d,&t)) {
if (0<=a && a<=255
&& 0<=b && b<=255
&& 0<=c && c<=255
&& 0<=d && d<=255) {
printf("[%s] is valid IPv4\n",s);
} else {
printf("[%s] is invalid IPv4\n",s);
原文
http://bbs.chinaunix.net/thread-928835-1-1.html
http://www.cnblogs.com/riky/archive/2006/11/24/570713.aspx
http://bbs.csdn.net/topics/330230349