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8086彙編0号中斷處理程式

版權聲明:本文可能為部落客原創文章,若标明出處可随便轉載。 https://blog.csdn.net/Jailman/article/details/79656110

**本篇代碼為王爽《彙編語言》實驗12正确答案,部分備援未作處理。

——————————-**

assume cs:code
    code segment

    start: mov ax,cs
           mov ds,ax
           mov si,offset do0
           mov ax,0
           mov es,ax
           mov di,200h
           mov cx,offset do0end-offset do0
           cld
           rep movsb
           mov ax,0
           mov es,ax
           mov word ptr es:[0*4],200h
           mov word ptr es:[0*4+2],0

           mov ax,1000h
           mov bh,1
           div bh

           mov ax,4c00h
           int 21h
    do0:   jmp short do0 start
              db "divide error!"

    do0start: mov ax,cs
              mov ds,ax
              mov si,202h

              mov ax,0b800h
              mov es,ax
              mov di,12*160+36*2

              mov cx,13

           s: mov al,[si]
              mov es:[di],al
              inc si
              add di,2
              loop s

              mov ax,4c00h
              int 21h

    do0end:nop
    code ends
    end start           

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