其實就是求兩個序列的最長公共子序列
代碼如下:
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
int n1,n2,Case=0;
while(scanf("%d%d",&n1,&n2)&&n1)
{
int a[110],b[110];
int dp[110][110],i,j;
memset(dp,0,sizeof(dp));
for(i=1;i<=n1;i++)
scanf("%d",&a[i]);
for(j=1;j<=n2;j++)
scanf("%d",&b[j]);
for(i=1;i<=n1;i++)
for(j=1;j<=n2;j++)
{
if(a[i]==b[j])
dp[i][j]=dp[i-1][j-1]+1;
else
dp[i][j]=max(dp[i-1][j],dp[i][j-1]);
}
printf("Twin Towers #%d\n",++Case);
printf("Number of Tiles : %d\n\n",dp[n1][n2]);
}
return 0;
}