select top 1000
*
from 费用表
where 费用ID<any ( select top 10
( 费用id )
from 费用表
order by 费用ID asc
)
where 费用ID>all ( select top 10
where 费用ID<some ( select top 10
from 费用表
order by 费用ID asc )
select top 1000
*
from 费用表
where 费用ID<any ( select top 10
( 费用id )
from 费用表
order by 费用ID asc
)
where 费用ID>all ( select top 10
where 费用ID<some ( select top 10
from 费用表
order by 费用ID asc )
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