我将图像资源存储在变量中，需要使用其HTTP API和PHP发送到服务器。 我必须发送内容类型为multipart / form-data的请求。 因此，当发送带有文件输入的表单并发送enctype = multipart / form-data属性时，我需要进行类似的请求。
我尝试了这个：
$url = 'here_is_url_for_web_API';
$input = fopen('delfin.jpg','r');
$header = array('Content-Type: multipart/form-data');
$resource = curl_init();
curl_setopt($resource, CURLOPT_URL, $url);
curl_setopt($resource, CURLOPT_USERPWD,"user:password");
curl_setopt($resource, CURLOPT_HTTPAUTH, CURLAUTH_ANYSAFE);
curl_setopt($resource, CURLOPT_HTTPHEADER, $header);
curl_setopt($resource, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($resource, CURLOPT_BINARYTRANSFER, true );
curl_setopt($resource, CURLOPT_INFILESIZE, 61631);
curl_setopt($resource, CURLOPT_INFILE, $input);
$result = curl_exec($resource);
curl_close($resource);
var_dump($result);
?>
我不知道响应应该是什么样子，但这返回：
http状态405
错误报告是：所请求的资源()不允许使用指定的HTTP方法。
在curl中使用multipart / form-data和POST内容中的边界。
$filenames = array("/tmp/1.jpg","/tmp/2.png");;
$files = array();
foreach ($filenames as $f){
$files[$f] = file_get_contents($f);
}
// more fields for POST request
$fields = array("f1"=>"value1","another_field2"=>"anothervalue");
$url ="http://example.com/upload";
$curl = curl_init();
$url_data = http_build_query($data);
$boundary = uniqid();
$delimiter = '-------------' . $boundary;
$post_data = build_data_files($boundary, $fields, $files);
curl_setopt_array($curl, array(
CURLOPT_URL => $url,
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_MAXREDIRS => 10,
CURLOPT_TIMEOUT => 30,
//CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
CURLOPT_CUSTOMREQUEST =>"POST",
CURLOPT_POST => 1,
CURLOPT_POSTFIELDS => $post_data,
CURLOPT_HTTPHEADER => array(
//"Authorization: Bearer $TOKEN",
"Content-Type: multipart/form-data; boundary=" . $delimiter,
"Content-Length:" . strlen($post_data)
),
));
//
$response = curl_exec($curl);
$info = curl_getinfo($curl);
//echo"code: ${info['http_code']}";
//print_r($info['request_header']);
var_dump($response);
$err = curl_error($curl);
echo"error";
var_dump($err);
curl_close($curl);
function build_data_files($boundary, $fields, $files){
$data = '';
$eol ="
";
$delimiter = '-------------' . $boundary;
foreach ($fields as $name => $content) {
$data .="--" . $delimiter . $eol
. 'Content-Disposition: form-data; name="' . $name .""".$eol.$eol
. $content . $eol;
}
foreach ($files as $name => $content) {
$data .="--" . $delimiter . $eol
. 'Content-Disposition: form-data; name="' . $name . '"; filename="' . $name . '"' . $eol
//. 'Content-Type: image/png'.$eol
. 'Content-Transfer-Encoding: binary'.$eol
;
$data .= $eol;
$data .= $content . $eol;
}
$data .="--" . $delimiter ."--".$eol;
return $data;
}
在此处查看完整的示例：https://gist.github.com/maxivak/18fcac476a2f4ea02e5f80b303811d5f
如果使用CURL，则必须：
1，将标头" Content-Type"设置为" multipart / form-data"；
2，将curl的选项" RETURNTRANSFER"设置为true(使用curl的选项方法)
3，将curl的选项'POST'设置为true(使用curl的选项方法)
4，获取文件的源代码(从PHP的fopen获取的内容)：
$tempFile = tempnam(sys_get_temp_dir(), 'File_');
file_put_contents($tempFile, $source);
$post = array(
"uploadedFile" =>"@" . $tempFile, //"@".$tempFile.";type=image/jpeg",
);
5，将CURL的post方法与$ post变量中的参数一起使用