1, 获取每天的零点
DateTime dt=new DateTime().withMillisOfDay(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-09 00:00:00
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2, 在每天的6:30处理一些东西
DateTime dt=new DateTime().withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-09 06:30:00
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3, 在每月的7号的6:30处理一些东西
DateTime dt=new DateTime().withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-09-07 06:30:00
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4, 在每年的8月的7号的6:30处理一些东西
DateTime dt=new DateTime().withMonthOfYear(8).withDayOfMonth(7).withHourOfDay(6).withMinuteOfHour(30).withSecondOfMinute(0);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));//结果2016-08-07 06:30:00
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5, 获取每个月的第一天和最后一天
DateTime dateTime=new DateTime();
System.out.println(dateTime.dayOfMonth().withMinimumValue().dayOfMonth().get());
System.out.println(dateTime.dayOfMonth().withMaximumValue().dayOfMonth().get());//结果130
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6, 获取每天的零点的下一天零点
DateTime dt=new DateTime().withMillisOfDay(0).plusDays(1);
System.out.println(dt.toString("yyyy-MM-dd HH:mm:ss"));
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7, 获取日期差
DateTime start=new DateTime(2015,5,4,12,20);
DateTime start=new DateTime(2015,5,4,12,20);
DateTime end=new DateTime(2015,5,6,3,10);
Period period=new Period(start,end);
System.out.println("month:"+period.getMonths());
System.out.println("days:"+period.getDays());
System.out.println("hours:"+period.getHours());
System.out.println("minutes:"+period.getMinutes());
System.out.println("second:"+period.getSeconds());//结果month:0days:1hours:14minutes:50second:0
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8, 单独获取天,小时,分钟,秒
DateTime start=new DateTime(2015,5,4,12,20);
DateTime end =new DateTime(2015,5,5,12,00);
System.out.println(Days.daysBetween(start,end).getDays());
System.out.println(Hours.hoursBetween(start,end).getHours());
System.out.println(Minutes.minutesBetween(start,end).getMinutes());
System.out.println(Seconds.secondsBetween(start,end));
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9, 时间判断是否在某个范围以及获取时间差的毫秒
DateTime start=new DateTime(2015,5,4,12,20);
DateTime end =new DateTime(2015,5,5,12,00);
Interval interval=new Interval(start,end);
System.out.println(interval.contains(new DateTime(2015,5,5,11,00)));
Duration duration=new Duration(start,end);
System.out.println(duration.getStandardHours());
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官网连接
http://www.joda.org/joda-time/userguide.html