Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* sortedArrayToBST(vector<int>& nums) {
if(nums.size()==)
return NULL;
if(nums.size()==)
return new TreeNode(nums[]);
int mid = nums.size()/;
vector<int>vleft(nums.begin(),nums.begin()+mid);
vector<int>vright(nums.begin()+mid+,nums.end());
TreeNode *T = new TreeNode(nums[mid]);
T->left = sortedArrayToBST(vleft);
T->right = sortedArrayToBST(vright);
return T;
}
};