python 服务运行,如何在Windows中将Python脚本作为服务运行？

I am sketching the architecture for a set of programs that share various interrelated objects stored in a database. I want one of the programs to act as a service which provides a higher level interface for operations on these objects, and the other programs to access the objects through that service.

I am currently aiming for Python and the Django framework as the technologies to implement that service with. I'm pretty sure I figure how to daemonize the Python program in Linux. However, it is an optional spec item that the system should support Windows. I have little experience with Windows programming and no experience at all with Windows services.

Is it possible to run a Python programs as a Windows service (i. e. run it automatically without user login)? I won't necessarily have to implement this part, but I need a rough idea how it would be done in order to decide whether to design along these lines.

Edit: Thanks for all the answers so far, they are quite comprehensive. I would like to know one more thing: How is Windows aware of my service? Can I manage it with the native Windows utilities? What is the equivalent of putting a start/stop script in /etc/init.d?

解决方案

Yes you can. I do it using the pythoncom libraries that come included with ActivePython or can be installed with pywin32 (Python for Windows extensions).

This is a basic skeleton for a simple service:

import win32serviceutil

import win32service

import win32event

import servicemanager

import socket

class AppServerSvc (win32serviceutil.ServiceFramework):

_svc_name_ = "TestService"

_svc_display_name_ = "Test Service"

def __init__(self,args):

win32serviceutil.ServiceFramework.__init__(self,args)

self.hWaitStop = win32event.CreateEvent(None,0,0,None)

socket.setdefaulttimeout(60)

def SvcStop(self):

self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)

win32event.SetEvent(self.hWaitStop)

def SvcDoRun(self):

servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,

servicemanager.PYS_SERVICE_STARTED,

(self._svc_name_,''))

self.main()

def main(self):

pass

if __name__ == '__main__':

win32serviceutil.HandleCommandLine(AppServerSvc)

Your code would go in the main() method—usually with some kind of infinite loop that might be interrupted by checking a flag, which you set in the SvcStop method