题意
问凑成 xn 最少需要几次
思路
好像前面也有一道类似的。用DFSID就行。也可以打表交
代码
- #include <cstdio>
- #include <stack>
- #include <set>
- #include <iostream>
- #include <string>
- #include <vector>
- #include <queue>
- #include <functional>
- #include <cstring>
- #include <algorithm>
- #include <cctype>
- #include <string>
- #include <map>
- #include <iomanip>
- #include <cmath>
- #define LL long long
- #define ULL unsigned long long
- #define SZ(x) (int)x.size()
- #define Lowbit(x) ((x) & (-x))
- #define MP(a, b) make_pair(a, b)
- #define MS(arr, num) memset(arr, num, sizeof(arr))
- #define PB push_back
- #define F first
- #define S second
- #define ROP freopen("input.txt", "r", stdin);
- #define MID(a, b) (a + ((b - a) >> 1))
- #define LC rt << 1, l, mid
- #define RC rt << 1|1, mid + 1, r
- #define LRT rt << 1
- #define RRT rt << 1|1
- #define BitCount(x) __builtin_popcount(x)
- #define BitCountll(x) __builtin_popcountll(x)
- #define LeftPos(x) 32 - __builtin_clz(x) - 1
- #define LeftPosll(x) 64 - __builtin_clzll(x) - 1
- const double PI = acos(-1.0);
- const int INF = 0x3f3f3f3f;
- using namespace std;
- const double eps = 1e-6;
- const int MAXN = 1100 + 10;
- const int MOD = 1000007;
-
- typedef pair<int, int> pii;
- typedef vector<int>::iterator viti;
- typedef vector<pii>::iterator vitii;
-
- int n, arr[MAXN], depth;
-
- bool DFSID(int curDep)
- {
- int pre = arr[curDep - 1];
- if (curDep == depth)
- {
- if (pre == n) return true;
- return false;
- }
- if (pre << (depth - curDep) < n) return false;
- for (int i = 0; i < curDep; i++)
- {
- arr[curDep] = pre + arr[i];
- if (arr[curDep] <= 1000 && DFSID(curDep + 1)) return true;
- arr[curDep] = pre - arr[i];
- if (arr[curDep] > 0 && DFSID(curDep + 1)) return true;
- }
- return false;
- }
-
- int main()
- {
- // ROP;
- int i, j;
- while (scanf("%d", &n), n)
- {
- arr[0] = 1;
- depth = 1;
- while (!DFSID(1)) depth++;
- printf("%d\n", depth - 1);
- }
- return 0;
- }