http://www.cnblogs.com/looker_acm/archive/2010/08/15/1799919.html
/*
** 混合图欧拉回路
** 只记录各定点的出度与入度之差,有向边无用丢弃,将无向边定向,在网络中建立流量为1的边
** 另新建s和t。对于入 > 出的点u,连接边(u, t)、容量为x,对于出 > 入的点v,连接边(s, v),
** 容量为x(注意对不同的点x不同)。之后,察看是否有满流的分配,如果是满流则存在,否则不存在
*/
#include <iostream>
#include <cstdio>
#include <cstring>
#include <queue>
#include <cmath>
using namespace std;
const int maxn = 300;
const int maxm = maxn*10;
struct node{
int v,next,flow;
}edge[maxm];
int head[maxn],dis[maxn],deg[maxn];
int id,source,sink;
void add_edge(int u,int v,int flow){
edge[id].v = v;edge[id].flow = flow;edge[id].next = head[u];head[u] = id++;
edge[id].v = u;edge[id].flow = 0 ;edge[id].next = head[v];head[v] = id++;
}
bool spfa(){
memset(dis,-1,sizeof(dis));
dis[source] = 0;
queue<int>que;
que.push(source);
while(!que.empty()){
int u = que.front();
que.pop();
for(int id = head[u]; id != -1; id = edge[id].next){
int v = edge[id].v;
if( edge[id].flow > 0 && dis[v] == -1){
dis[v] = dis[u] + 1;
que.push(v);
}
}
}
return dis[sink] != -1;
}
int dinic(int u,int flow){
if( u == sink)return flow;
int tmp = flow;
for(int id = head[u]; id != -1; id = edge[id].next){
int v = edge[id].v;
if( edge[id].flow > 0 && dis[v] == dis[u] + 1){
int tt = dinic(v,min(edge[id].flow ,tmp));
tmp -= tt;
edge[id].flow -= tt;
edge[id^1].flow += tt;
if( tmp == 0)return flow;
}
}
return flow - tmp;
}
int get_max(){
int max_flow = 0;
while( spfa())
max_flow += dinic(source,100000);
return max_flow;
}
int main(){
int t,n,m;
int u,v,d;
scanf("%d",&t);
while( t-- ){
scanf("%d%d",&n,&m);
for(int i = 0; i <= n+1; i++)
deg[i] = 0,head[i] = -1;
id = source = 0;sink = n+1;
while( m-- ){
scanf("%d%d%d",&u,&v,&d);
if( u == v)continue;
deg[u]++,deg[v]--;
if( d == 0)add_edge(u,v,1);
}
bool flg = false;
int ans = 0;
for(int i = 1;i <= n; i++){
if( deg[i]%2 ){flg = true;break;}
deg[i] /= 2;
if( deg[i] > 0){
ans += deg[i];
add_edge(source,i,deg[i]);
}
else
add_edge(i,sink,-deg[i]);
}
if( flg || ans != get_max())puts("impossible");
else puts("possible");
}
return 0;
}
转载于:https://www.cnblogs.com/LUO257316/p/3288564.html