Problem C: 点在圆内吗?
Description
定义一个Point类和Circle类,用于判断给定的一系列的点是否在给定的圆内。
其中,Point类:
1.有2个成员x和y,分别为其横坐标和纵坐标;1个静态成员numOfPoints,用于计算生成的点的个数。
2.具有构造函数、析构函数和拷贝构造函数,具体格式输出根据样例自行判断。
3. 具有静态方法int getNumOfPoints(),用于返回numOfPoints的值。
4. 具有int getX()和int getY()方法,用于获取横坐标和纵坐标。
Circle类:
1. 拥有Point类的对象center,表示圆心坐标。拥有radius对象,表示圆的半径;1个静态成员numOfCircles,用于指示生成了多少个圆对象。
2. 具有构造函数、析构函数和拷贝构造函数,具体格式根据样例自行判断。
3.具有静态方法int getNumOfCircles(),返回numOfCircles的值。
4. 具有getCenter()方法,返回圆心坐标。注意:根据输出结果判断返回值类型。
5. 具有bool pointInCircle(Point &)方法,用于判断给定的点是否在当前圆内。是则返回true,否则返回false。
Input
输入分多行。
第一行M>0,表示有M个测试用例。
每个测试用例又包括多行。第1行包含3个整数,分别为一个圆的横坐标、纵坐标和半径。第2行N>0,表示之后又N个点,每个点占一行,分别为其横坐标和纵坐标。
所有输入均为整数,且在int类型范围内。
Output
输出见样例。注意:在圆的边上的点,不在圆内。
#include <iostream>
using namespace std;
class Point {
private:
int x, y;
static int numOfPoint;
public:
Point(int xx = 0, int yy = 0) : x(xx), y(yy) {
numOfPoint++;
cout << "The Point ("<<x<<", "<<y<<") is created! Now, we have "<<numOfPoint<<" points." << endl;
}
Point(const Point &another) {
x = another.x, y = another.y;
numOfPoint++;
cout << "A Point ("<<x<<", "<<y<<") is copied! Now, we have "<<numOfPoint<<" points." << endl;
}
~Point() {
numOfPoint--;
cout << "A Point ("<<x<<", "<<y<<") is erased! Now, we have "<<numOfPoint<<" points." << endl;
}
int getX() { return x; }
int getY() { return y; }
static int getNumOfPoints() { return numOfPoint; }
};
class Circle {
private:
Point center;
int r;
static int numOfCircle;
public:
Circle(int x, int y, int r) : center(x, y), r(r) {
numOfCircle++;
cout << "A circle at ("<<x<<", "<<y<<") and radius "<<r<<" is created! Now, we have "<<numOfCircle<<" circles." << endl;
}
Circle(Point p, int r) : center(p), r(r) {
numOfCircle++;
int x = p.getX(), y = p.getY();
cout << "A circle at ("<<x<<", "<<y<<") and radius "<<r<<" is created! Now, we have "<<numOfCircle<<" circles." << endl;
}
~Circle() {
numOfCircle--;
int x = center.getX(), y = center.getY();
cout << "A circle at ("<<x<<", "<<y<<") and radius "<<r<<" is erased! Now, we have "<<numOfCircle<<" circles." << endl;
}
bool pointInCircle(Point &p) {
int x0 = center.getX(), y0 = center.getY();
int x1 = p.getX(), y1 = p.getY();
int len = (x1 - x0) * (x1 - x0) + (y1 - y0) * (y1 - y0);
if (len < r * r) return true;
else return false;
}
Point &getCenter() {
Point &temp = center;
return temp;
}
static int getNumOfCircles() { return numOfCircle; }
};
int Point::numOfPoint = 0;
int Circle::numOfCircle = 0;
int main()
{
int cases,num;
int x, y, r, px, py;
Point aPoint(0,0), *bPoint;
Circle aCircle(1,1,1);
cin>>cases;
cout<<"We have "<<Point::getNumOfPoints()<<" points and "<<Circle::getNumOfCircles()<<" circles now."<<endl;
for (int i = 0; i < cases; i++)
{
cin>>x>>y>>r;
bPoint = new Point(x,y);
Circle circle(*bPoint, r);
cin>>num;
for (int j = 0; j < num; j++)
{
cin>>px>>py;
if (circle.pointInCircle(*(new Point(px, py))))
{
cout<<"("<<px<<", "<<py<<") is in the circle at (";
cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
}
else
{
cout<<"("<<px<<", "<<py<<") is not in the circle at (";
cout<<circle.getCenter().getX()<<", "<<circle.getCenter().getY()<<")."<<endl;
}
}
delete bPoint;
}
cout<<"We have "<<Point::getNumOfPoints()<<" points, and "<<Circle::getNumOfCircles()<<" circles."<<endl;
return 0;
}