[树状数组] poj1195 Mobile phones

题目分析

    二维树状数组，单点更新、区间查询

代码

#include<iostream>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>
#include<map>
#include<algorithm>
using namespace std;
const int maxn=+;
int bit[maxn][maxn];
int n;
inline int lowbit(int x)
{
    return x&-x;
}
void add(int x,int y,int val)
{
    for(int i=x;i<=n;i+=lowbit(i))
        for(int j=y;j<=n;j+=lowbit(j))
            bit[i][j]+=val;
}
int getsum(int x,int y)
{
    int res=;
    for(int i=x;i>;i-=lowbit(i))
        for(int j=y;j>;j-=lowbit(j))
            res+=bit[i][j];
    return res;
}
int calc(int x1,int y1,int x2,int y2)
{
    return getsum(x2,y2)-getsum(x1-,y2)-getsum(x2,y1-)+getsum(x1-,y1-);
}
int main()
{
    int op;
    memset(bit,,sizeof bit);
    while(cin>>op)
    {
        switch(op)
        {
            case :cin>>n;break;
            case :
            {
                int x,y,z;
                scanf("%d%d%d",&x,&y,&z);
                add(x+,y+,z);
                break;
            }
            case :
            {
                int x1,y1,x2,y2;
                scanf("%d%d%d%d",&x1,&y1,&x2,&y2);
                cout<<calc(x1+,y1+,x2+,y2+)<<endl;
                break;
            }
        }
    }
    return ;
}