原題網址:https://leetcode.com/problems/clone-graph/
Clone an undirected graph. Each node in the graph contains a
label
and a list of its
neighbors
.
OJ's undirected graph serialization:
Nodes are labeled uniquely.
We use
#
as a separator for each node, and
,
as a separator for node label and each neighbor of the node.
As an example, consider the serialized graph
{0,1,2#1,2#2,2}
.
The graph has a total of three nodes, and therefore contains three parts as separated by
#
.
- First node is labeled as . Connect node to both nodes
and1
.2
- Second node is labeled as
. Connect node1
to node1
.2
- Third node is labeled as
. Connect node2
to node2
(itself), thus forming a self-cycle.2
Visually, the graph looks like the following:
1
/ \
/ \
0 --- 2
/ \
\_/
方法:使用哈希映射儲存已克隆的節點。
/**
* Definition for undirected graph.
* class UndirectedGraphNode {
* int label;
* List<UndirectedGraphNode> neighbors;
* UndirectedGraphNode(int x) { label = x; neighbors = new ArrayList<UndirectedGraphNode>(); }
* };
*/
public class Solution {
private Map<Integer, UndirectedGraphNode> map = new HashMap<>();
public UndirectedGraphNode cloneGraph(UndirectedGraphNode node) {
if (node == null) return null;
UndirectedGraphNode cloned = map.get(node.label);
if (cloned != null) return cloned;
cloned = new UndirectedGraphNode(node.label);
map.put(cloned.label, cloned);
for(UndirectedGraphNode neighbor: node.neighbors) {
cloned.neighbors.add(cloneGraph(neighbor));
}
return cloned;
}
}