hdu 1985

Conversions

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 1124    Accepted Submission(s): 647

Problem Description Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

Input The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

Output For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

Sample Input

5
1 kg
2 l
7 lb
3.5 g
0 l
        

Sample Output

1 2.2046 lb
2 0.5284 g
3 3.1752 kg
4 13.2489 l
5 0.0000 g
        

Source 2008 “Shun Yu Cup” Zhejiang Collegiate Programming Contest - Warm Up（1）  

Recommend linle  

//該題就是簡單的機關換算
#include <stdio.h>
#include <string.h>
int main()
{
	int n, i;
	double in;
	char c[3];
	scanf("%d", &n);
	for (i = 1; i <= n; i++)
	{
		scanf("%lf%s", &in, c);
		if (strcmp(c, "kg") == 0)
			printf("%d %.4lf lb\n", i, in*2.2046);
		else if (strcmp(c, "lb") == 0)
			printf("%d %.4lf kg\n", i, in*0.4536);
		else if (strcmp(c, "l") == 0)
			printf("%d %.4lf g\n", i, in*0.2642);
		else if (strcmp(c, "g") == 0)
			printf("%d %.4lf l\n", i, in*3.7854);
	}
	return 0;
}