Comrade Dujikov is busy choosing artists for Timofey’s birthday and is
recieving calls from Taymyr from Ilia-alpinist.
Ilia-alpinist calls every n minutes, i.e. in minutes n, 2n, 3n and so
on. Artists come to the comrade every m minutes, i.e. in minutes m,
2m, 3m and so on. The day is z minutes long, i.e. the day consists of
minutes 1, 2, …, z. How many artists should be killed so that there
are no artists in the room when Ilia calls? Consider that a call and a
talk with an artist take exactly one minute. Input
The only string contains three integers — n, m and z
(1 ≤ n, m, z ≤ 104). Output
Print single integer — the minimum number of artists that should be
killed so that there are no artists in the room when Ilia calls.
容易發現需要殺掉的就是 x∗lcm(n,m) 。
#include<cstdio>
int gcd(int a,int b)
{
return b?gcd(b,a%b):a;
}
int lcm(int a,int b)
{
return a/gcd(a,b)*b;
}
int main()
{
int m,n,k;
scanf("%d%d%d",&n,&m,&k);
printf("%d\n",k/lcm(n,m));
}