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第二次作业

1 package aaa;
 2 import java.util.Scanner;
 3 
 4 public class A {
 5     
 6     public static void main(String[]args)
 7     {   
 8         int[] arr1={-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,
-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,
2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,
6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,
461,940,6604,-3631,3802,-2037,-4354,-1213,767};
 9         int sum=0;
10         Scanner se = new Scanner(System.in) ;
11         System.out.println("请输入start:");
12         int start = se.nextInt() ; 
13         System.out.println("请输入end:");
14         int end =se.nextInt();
15         System.out.println("start为:" +start);
16         System.out.println("end为:" +end);
17         for(int i=start;i<=end;i++)18 19 
20             sum+=arr1[i];                             
21         System.out.println(sum);  
22    }
23     
24               }      

这上面是一维数组1至100任意相加的代码,运用了面向过程的方法。需要输入一维数的开始范围与结束范围,由程序最后自动相加得到结果。

1 package aaa;
 2 
 3 import java.util.Scanner;
 4 
 5 public class B {
 6     
 7     public static void main(String[]args){
 8         int[][] a={{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767},{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}};
 9         int sum=0;
10         Scanner se = new Scanner(System.in);
11         System.out.println("输入start-y:");
12         int start1 = se.nextInt(); 
13         System.out.println("输入end-y:");
14         int end1 =se.nextInt();
15         System.out.println("start-y:" +start1);
16         System.out.println("end-y:" +end1);
17         
18         System.out.println("输入start-x:");
19         int start2 = se.nextInt(); 
20         System.out.println("输入end-x:");
21         int end2 =se.nextInt();
22         System.out.println("start-x:" +start2);
23         System.out.println("end-x:" +end2);
24         for(int i=start1;i<=end1;i++)
25         {
26             for(int j=start2;j<=end2;j++)
27             {
28             sum+=a[i][j];
29             }
30         }
31         System.out.println(sum);  
32     }
33 
34 }      

这上面是二维数组,同样运用了面向过程的方法。

1 package aaa;
 2 
 3 import java.util.Scanner;
 4 
 5 public class C {
 6 
 7     
 8     public static void main(String[]args)
 9     {
10         int sum=0;
11          int[][][] a = new int[][][]
12             {
13                 {{-2574,-4010,8243,771,2447,-5197,2556,8044,3314,3617,6065,-2817,3131,6318,2186,-113,629,-2582,-37,-1520,164,2055,-5936,5912,1717,5988,4781,5757,892,-4394,8034,2213,-1080,-2080,5364,106,2657,566,3940,-5116,4583,1806,6555,2621,-7197,528,1626,18,1049,6243,3198,4397,-1325,9087,936,-6291,662,-178,135,-3473,-2385,-165,1713,-7949,-4234,1138,2212,104,6968,-3632,3801,1137,-1296,-1215,4272,6223,-5922,-7723,7044,-2938,-8180,1356,1159,-4022,-3713,1158,-8715,-4081,-2541,-2555,-2284,461,940,6604,-3631,3802,-2037,-4354,-1213,767}}, 
14                 {{2740,-4182,-5632,-2966,-1953,567,-8570,1046,2211,1572,-2503,-1899,3183,-6187,3330,3492,-464,-2104,316,8136,470,50,466,-1424,5809,2131,6418,-3018,6002,-8379,1433,1144,2124,1624,-602,-5518,5872,870,-5175,-3961,-427,-6284,2850,481,6175,141,-766,-1897,-748,-4248,366,4823,3003,1778,3256,2182,2253,5076,5540,-2650,2451,-1875,5482,-6881,-329,-969,-8032,-2093,612,1524,-5492,5758,-7401,-5039,3241,6338,3581,4321,-1072,4942,2131,210,-7045,-7514,7450,-1142,-2666,-4485,-639,2121,-5298,-3805,-1686,-2520,-1680,2321,-4617,-1961,2076,7309}},
15                 {{302,-7944,-6551,6648,-884,-6332,1188,-248,3902,-2171,-3782,-3510,6203,-636,-4605,4497,3187,-6278,1198,-7963,7647,-3022,-8267,7995,-1998,-4171,730,-8117,-1706,7601,-2454,-6161,-1810,243,-2841,-5377,2985,2328,177,5622,3596,3057,2830,-1151,6566,2254,6972,-3060,4063,367,84,3156,3880,-1530,5272,1385,-565,-1736,1267,-3863,-229,2072,2423,-7449,9555,2844,-1278,-3613,-919,4153,-4232,4032,-5732,199,4792,2498,-3344,-4193,2650,-579,3416,-3575,1822,-6936,-2661,-1873,414,2314,6844,7613,-7844,6680,5974,2208,-3597,6302,4396,-141,-1864,1939}}
16             };
17         Scanner se = new Scanner(System.in) ;
18         System.out.println("请输入start-x:");
19         int start1 = se.nextInt() ; 
20         System.out.println("请输入end-x:");
21         int end1 =se.nextInt();
22         System.out.println("start-x为:" +start1);
23         System.out.println("end-x为:" +end1);
24         
25         System.out.println("请输入start-y:");
26         int start2 = se.nextInt() ; 
27         System.out.println("请输入end-y:");
28         int end2 =se.nextInt();
29         System.out.println("start-y为:" +start2);
30         System.out.println("end-y为:" +end2);
31         
32         System.out.println("请输入start-z:");
33         int start3 = se.nextInt() ; 
34         System.out.println("请输入end-z:");
35         int end3 =se.nextInt();
36         System.out.println("start-z为:" +start3);
37         System.out.println("end-z为:" +end3);
38         for(int i=start1;i<=end1;i++)
39          {
40              for(int j=start2;j<=end2;j++)
41             {
42                  for(int q=start3;q<=end3;q++)
43                  {
44                      sum+=a[i][j][q];         
45             
46                  }
47             }
48              
49          }
50          System.out.println(sum);
51     }
52 }      

此为三维数组。